What is y=3(x-1)^2+5 in standard form?

standard form is y = ax^2 + bx + c

so expanding, y = 3(x^2 - 2x + 1) + 5
= 3x^2 - 6x + 3 + 5
= 3x^2 - 6x + 8

so y = 3x^2 - 6x + 8

"Confused" is correct. Follow his/her steps.

3(x-1)²+5
3(x²-2x+1)+5
3x²-6x+3+5
3x²-6x+8

the structure of standard form is y=ax^2+bx+c

step 1: expand (x-1)^2
y=3(x-1)^2+5
y=3(x^2-2x+1)+5

step 2: distribute the constant "3" to (x^2-2x+1)
y=3x^2-6x+3+5

step 3: combining like terms
y=3x^2-6x+8