Xsquare=8X+7 solve for x?
回答 (10)
2009-06-17 2:34 pm
✔ 最佳答案
x^2 - 8x = 7 add 4^2 to both sides u get:
x^2 - 8x + 16 = 7 + 16
(x - 4)^2 = 23
x - 4 = +/- sqrt(23)
x = 4 +/- sqrt(23)
2009-06-17 2:34 pm
x^2 = 8x + 7
x^2 - 8x - 7 = 0
Now use the formula for solving a quadratic....
Ans = -b (+-sqrt(b^2 - 4ac) / 2a) to get your 2 values out.
x^2 - 8x - 7 = 0
Now use the formula for solving a quadratic....
Ans = -b (+-sqrt(b^2 - 4ac) / 2a) to get your 2 values out.
2009-06-17 2:34 pm
x^2=8x+7
x^2-8x=7
x^2-8x+16 = 7+16
(x-4)^2 = 23
x-4 = +/- sqrt(23)
x = 4 +/- sqrt(23)
x^2-8x=7
x^2-8x+16 = 7+16
(x-4)^2 = 23
x-4 = +/- sqrt(23)
x = 4 +/- sqrt(23)
2009-06-17 2:32 pm
assuming xsquare means x^2, x=-8 and 1.
x^2=8x+7
x^2-8x-7=0
(x-8)*(x+1)=0
x-8=0 x+1=0
x=8 x=-1
x^2=8x+7
x^2-8x-7=0
(x-8)*(x+1)=0
x-8=0 x+1=0
x=8 x=-1
2009-06-17 2:37 pm
x=4±√23;
ie, x=8.79 or x= - .79
ie, x=8.79 or x= - .79
2009-06-17 2:36 pm
x^2-8x-7=0
x=[4+&-(16+7)^1/2]=8.7958315 & -0.7958315
x=[4+&-(16+7)^1/2]=8.7958315 & -0.7958315
2016-12-14 11:49 pm
the answer isn't confusing, yet first permit's back up and initiate from the beginning up. generally you will settle for an equation to remedy for x. it may be x^2 -12x+35=0 one thank you to remedy this equation is to ingredient it. in case you gain this which you get (x-7)(x-5)=0 Now which you have arrived at those factors, what next? properly, on account that the two factors prolonged mutually equivalent 0, then the two x-7=0, or x-5=0 So x is 7 or 5. it somewhat is your answer . x=7,5
2009-06-17 6:38 pm
x² = 8x + 7
Move everything to the left side
x² - 8x - 7 = 0
Use quadratic formula to solve for x.
x = x = 4 ±√23
Move everything to the left side
x² - 8x - 7 = 0
Use quadratic formula to solve for x.
x = x = 4 ±√23
2009-06-17 2:57 pm
x= 4+/-sqrt23
2009-06-17 2:35 pm
x^2 = 8x + 7
x^2 - 8x - 7 = 0
x = [-b ±√(b^2 - 4ac)]/(2a)
a = 1
b = -8
c = -7
x = [8 ±√(64 + 28)]/2
x = [8 ±√92]/2
x = [8 ±√(2^2 * 23)]/2
x = [8 ±2√23]/2
x = 4 ±√23
∴ x = 4 ±√23
x^2 - 8x - 7 = 0
x = [-b ±√(b^2 - 4ac)]/(2a)
a = 1
b = -8
c = -7
x = [8 ±√(64 + 28)]/2
x = [8 ±√92]/2
x = [8 ±√(2^2 * 23)]/2
x = [8 ±2√23]/2
x = 4 ±√23
∴ x = 4 ±√23
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