AL electrostatic charge(15pts)

There will be a decrease of electrical energy.
A sphere can be considered as a capacitor. The energy stored in the sphere = (1/2)QV
where Q is the charge on the sphere and V is the potential of the sphere.
For simplicity, assume the other sphere is identical to the first one. Hence, after coonection, the second sphere shares half of the original charge of the first sphere, i.e. Q/2
Since the potential on a sphere is proportional to its charge, the potential of the first sphere (with charge Q/2 remains) becomes V/2.
Energy of the first sphere = (1/2)(Q/2)(V/2) = QV/8
This is also equal to the energy of the second sphere. Total energy of the two spheres = 2 x (QV/8) = QV/4
Therefore, the change of total energy
= QV/4 - QV/2 = - QV/4
Although the above explanation is for two identical spheres, it would be expected that there is also a loss of energy if the two spheres are not the same.

Two isolated sphere, one has positive charge, one has zero charge, are NOT in contact at the begining.

Account for any change in the total electrical energy on the two spheres after they are connected by a conducting wire.
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1. There will have no change in electrical energy.( The electrical energy will only transfer to the other ball with zero charge)

2. The zero charged ball will be positive after they contact each other.(The ball was charged by conduction)

3. After it is connected by a conducting wire, the electrons will be earthed to the ground.

Hope these can help you.