4x-4=4x
x+5=-5x+5
x-1=5x+3x-8
x--4=-9+x
12=-4(-6x - 3)
24x-22=-4(1-6x)
what is the value of x in these problems?
2009-06-16 12:41 pm
回答 (8)
2009-06-16 12:50 pm
✔ 最佳答案
1)4x - 4 = 4x
4x - 4x = 4
0 = 4
(no solutions)
2)
x + 5 = -5x + 5
x + 5x = -5 + 5
6x = 0
x = 0/6
x = 0
3)
x - 1 = 5x + 3x - 8
x - 1 = 8x - 8
x - 8x = 1 - 8
-7x = -7
x = -7/(-7)
x = 1
4)
x - 4 = -9 + x
x - x = -9 + 4
0 = -5
(no solutions)
5)
12 = -4(-6x - 3)
12/(-4) = -6x - 3
-3 = -6x - 3
6x = 3 - 3
x = 0/6
x = 0
6)
24x - 22 = -4(1 - 6x)
24x - 22 = -4*1 + 4*6x
24x - 22 = -4 + 24x
24x - 24x = -4 + 22
0 = 18
(no solutions)
2009-06-16 8:17 pm
4x - 4 = 4x is not an equation—no solution to this problem.
x + 5 = - 5x + 5
6x = 0
x = 0
x - 1 = 5x + 3x - 8
8x - x = - 1 + 8
7x = 7
x = 1
x - (- 4) = - 9 + x there's no solution to this problem.
12 = - 4(- 6x - 3)
12 = 24x + 12
24x = 0
x = 0
24x - 22 = - 4(1 - 6x) there's no solution to this problem.
x + 5 = - 5x + 5
6x = 0
x = 0
x - 1 = 5x + 3x - 8
8x - x = - 1 + 8
7x = 7
x = 1
x - (- 4) = - 9 + x there's no solution to this problem.
12 = - 4(- 6x - 3)
12 = 24x + 12
24x = 0
x = 0
24x - 22 = - 4(1 - 6x) there's no solution to this problem.
2009-06-16 7:52 pm
1)no solution
2)x=0
3)x=1
4)no solution
5)x=0
6)no solution
2)x=0
3)x=1
4)no solution
5)x=0
6)no solution
2009-06-16 7:52 pm
Use the order of operations! This is simple algebra that should be easy to solve, as long as you can understand basic concepts.
Not solving for you, because these look something like problems from homework! So, some reminders.
-Order of Operations
-The Distributive, Associative, and Commutative Properties are important.
-Isolating x should be one of the first steps.
-Remember to check! And make sure that not ALL of the problems have single solutions, as I can see from the first problem.
Not solving for you, because these look something like problems from homework! So, some reminders.
-Order of Operations
-The Distributive, Associative, and Commutative Properties are important.
-Isolating x should be one of the first steps.
-Remember to check! And make sure that not ALL of the problems have single solutions, as I can see from the first problem.
2009-06-16 7:51 pm
ax=b
x=b/a
x=b/a
2009-06-16 7:51 pm
4x-4=4x
--> 4x-4x=4 taking common
--> 4(x)=4
--> x=1
man these are k.g. class problems
--> 4x-4x=4 taking common
--> 4(x)=4
--> x=1
man these are k.g. class problems
2009-06-16 7:48 pm
/
1)no solution
2)x=0
3)x=1
1)no solution
2)x=0
3)x=1
2009-06-16 7:48 pm
x+5=-5x+5 => 6x = 0 => x = 0.
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