I need help on my polynomials question,
-10 a^5 b^8 / 18 a^ 5b ^6
The answer is 5 b^2 /9
I understand how b^2, but what did you have to do to get 5/9?
Polynomials Equation?
2009-06-16 7:58 am
回答 (5)
2009-06-16 8:08 am
✔ 最佳答案
it is not 5 b^2 /9but -5 b^2/9
- 5/9 comes when we devide -10 by 18
2009-06-16 8:24 pm
= - 10a⁵b⁸/18a⁵b⁶ divide both numerator & denominator with 2a⁵b⁶
= (- 10a⁵b⁸/2a⁵b⁶)/(18a⁵b⁶/2a⁵b⁶)
= - 5b²/9 OR - 5/9b²
Answer: - 5b²/9 OR - 5/9b²
Step by step:
= - 10a⁵b⁸/18a⁵b⁶ divide numerator & denominator by a⁵
= (- 10a⁵b⁸/a⁵)/(18a⁵b⁶/a⁵)
= - 10b⁸/18b⁶ divide numerator & denominator by b⁶
= (- 10b⁸/b⁶)/(18b⁶/b⁶)
= - 10b²/18 divide numerator & denominator by 2
= (- 10b²/2)/(18/2)
= - 5b²/9 OR - 5/9b²
= (- 10a⁵b⁸/2a⁵b⁶)/(18a⁵b⁶/2a⁵b⁶)
= - 5b²/9 OR - 5/9b²
Answer: - 5b²/9 OR - 5/9b²
Step by step:
= - 10a⁵b⁸/18a⁵b⁶ divide numerator & denominator by a⁵
= (- 10a⁵b⁸/a⁵)/(18a⁵b⁶/a⁵)
= - 10b⁸/18b⁶ divide numerator & denominator by b⁶
= (- 10b⁸/b⁶)/(18b⁶/b⁶)
= - 10b²/18 divide numerator & denominator by 2
= (- 10b²/2)/(18/2)
= - 5b²/9 OR - 5/9b²
2009-06-16 3:47 pm
-10a^5b^8/(18a^5b^6)
= (-10/18)(a^5/a^5)(b^8/b^6)
= (-5/9)[a^(5 - 5)][b^(8 - 6)]
= (-5/9)(a^0)(b^2)
= (-5/9)(1)(b^2)
= (-5/9)(b^2)
= -5b^2/9
= (-10/18)(a^5/a^5)(b^8/b^6)
= (-5/9)[a^(5 - 5)][b^(8 - 6)]
= (-5/9)(a^0)(b^2)
= (-5/9)(1)(b^2)
= (-5/9)(b^2)
= -5b^2/9
2009-06-16 3:10 pm
=(-1/9)b^2
2009-06-16 3:05 pm
dunno...
收錄日期: 2021-05-01 12:32:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090615235841AAd4WxO