maths _29

回答 (1)

2009-06-14 4:45 am
✔ 最佳答案
The answers are:
(38) A
(40) D
(42) A
(47) B
(49) C

2009-06-13 21:04:37 補充:
Let CF=x
MN =0.5x
BM=0.5x/sin30 = x
AM^2=AB^2+BM^2=9x^2+x^2=10x^2
AM=sqrt(10)x
sine of angle = MN/AM=0.5x/sqrt(10)x=0.158
angle=9.1

2009-06-13 21:06:40 補充:
f(x) divisible by x+1 so f(-1)=0
(-1)^16-9(-1)+k=0
1+9+k=0
k=-10

2009-06-13 21:09:19 補充:
g(x)=h(x)(2x-3)+R...(1)
g(x)=p(x)(3-2x)+R1...(2)
(1)=> g(3/2)=h(3/2)(0)+R
R=g(3/2)
(2)=> g(3/2)=p(3/2)+R1
R1=g(3/2)=R

2009-06-13 21:11:27 補充:
x^4-x^2-12=0
(x^2+3)(x^2-4)=0
x^2+3 cannot be zero
x=+2 or x=-2

2009-06-13 21:14:39 補充:
x-3/y=5...(1)
x+y=1
x=1-y
Sub into (1)
1-y-3/y=5
y-y^2-3=5y
y^2+4y+3=0
(y+3)(y+1)=0
y=-3; x=4
y=-1; x=2


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