a. (4x + 1)(16x2 + 1)
b. (4x + 1)(16x2 - 4x + 1)
c. (4x + 1)(16x2 - 4x - 1)
d. (4x + 1)(16x2 + 4x + 1)
Factor the polynomial completely. 64x^3 + 1?
2009-06-12 2:57 pm
回答 (6)
2009-06-12 4:22 pm
✔ 最佳答案
64x^3 + 1=(4x+1)(16x^2-4x+1) answer//answer is b. (4x + 1)(16x2 - 4x + 1)
2009-06-12 3:01 pm
(4x + 1)(16x^2 - 4x + 1)
2009-06-12 3:45 pm
a^3 + b^3 ≡ (a + b)(a^2 - ab + b^2)
64x^3 + 1
= (4x)^3 + 1^3
= (4x + 1)(16x^2 - 4x + 1)
(answer b)
64x^3 + 1
= (4x)^3 + 1^3
= (4x + 1)(16x^2 - 4x + 1)
(answer b)
2009-06-12 3:12 pm
a^3 + b^3 = (a+b)(a^2-ab+b^2)
64x^3 + 1 = (4x)^3+ (1)^3
= (4x+1)[(4x)^2 - (4x)(1) + (1)^2]
= (4x+1)(16x^2-4x+1)
64x^3 + 1 = (4x)^3+ (1)^3
= (4x+1)[(4x)^2 - (4x)(1) + (1)^2]
= (4x+1)(16x^2-4x+1)
2009-06-12 3:01 pm
B: (4 x+1) (16 x^2-4 x+1)
2009-06-12 3:00 pm
(4x + 1)(16x^2 + 4x + 1) :: D
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