x^2-x=10 use quadratic formula to solve?

x^2 - x = 10
x^2 - x - 10 = 0
x = [-b ±√(b^2 - 4ac)]/2a

a = 1
b = -1
c = -10

x = [1 ±√(1 + 40)]/2
x = [1 ±√41]/2

∴ x = [1 ±√41]/2

x² - x = 10

x² - x - 10 = 0

a = 1, b = -1, c = -10

........-b - √(b² - 4ac)
x1 = ------------------------
.................2a


.......-(-1) - √((-1)² - 4(1)(-10))
....= -----------------------------------
.................2(1)

..........1 - √(1 + 40)
....= -------------------------------
...................2

...........1 - √41
....= --------------------
...............2
.......1
...= ----(1 - √41)
.......2

or

.........1
x2 = ----(1 + √41)
.........2

x^2 - x - 10 = 0
x = [ - b ± √ (b ² - 4 a c ) ] / 2 a
x = [ 1 ± √ (1 + 40) ] / 2
x = [ 1 ± √ (41) ] / 2 is the answer which can be approximated to :-
x = [ 1 ± 6.4 ] / 2
x = 3.7 , x = - 2.7

x^2 - x = 10

x^2 - x - 10 = 0

[ 1 +/- sqrt(1^2 - 4(1)(10)) ] / 2(1)

[ 1 +/- sqrt(-39) ] / 2

Your solutions are going to be complex numbers because of the negative discriminant.

1 + 39i / 2

or

1 - 39i / 2

I forgot where to go from here... I don't think you use complex conjugates unless there is a complex number in the denominator (like there is in this case of the numerator).

But I'm not sure, I can't remember clearly.

(-1+-sqrt-39)/2 , the answer will be a complex conjugate, so then you can take the sqrt(-39) and get + or - 6.244i then divide -1 and 6.244 by 2 and your answer should be -(1/2)+ or - 3.1224i

http://www68.wolframalpha.com/input/?i=X^2-x%3D10

This is the full answer, complete with an integer graph.