✔ 最佳答案
http://hyperphysics.phy-astr.gsu.edu/hbase/pber.html
P1 + 0.5*rho*V1^2 + rho*g*h1 = P2 + 0.5*rho*V2^2 + rho*g*h2
We assume there is no change in elevation between the hose and the nozzle===> rho*g*h term drops out
We need velocities at the hose(1) and nozzle(2)
Flow Rate = velocity * cross-section
0.0005 m^^3/s = V1 *(pi*r1^2)
0.0005 = V1 *(pi * (4.5 *10^-2)^2)
V1 = 0.0005 / 0.0063 = 0.08 m/s
0.0005 = V2 * (pi *0.015^2)
V2 = 0.0005 / 0.00071 = 0.71 m/s
P1 + 0.5*rho*0.08^2 = P2 + 0.5*rho* 0.71^2
P1 - P2 = 3.2 * 10^-3 - 0.25
P1 - P2 = 0.0032 - 0.25 = - 0.2468 Pa
Check my math and units.