how will you factorise x^-4?

1 / x^4

or you just have (1/x, 1/x, 1/x, 1/x)

^^

=1/x^4

x^-4
= 1/(x^4)

1/x^4

factorize ..... errr it can't -- sorry

= 1/x^4 = (1/x)^4

Hi.

This is what is known as " A difference of two squares."

That is, a situation where each of the elements in the equation is a square of another number and the square root is thus easily found.

That is, X squared has a square root of X and 4 has a square root of 2.

Thus, the convention is to write the anser as (x - 2)(x + 2). That's it.

If you expand (x - 2)(x + 2), you will arrive at x^2 - 4.

Good day.



It occurs to me that I misread your question. In case I didn't, i will let the first part remain and include the other answer here as well.

Well, x^-4 = 1/x^4 = 1/(x^2)^2.

Good day.