✔ 最佳答案
By parallelogram law the angle, 'theta' that the aircraft velocity as seen on ground will make with air craft velocity with respect to wind is given by
theta = tan^-1[35 sin40/(180 + 35 cos 40)] = tan^-1[0.109] = 6.2 degrees. However the required answer is 40 - 6.2 = 33.8 east of north.
On ground the aircraft would move 33.8 degree east of north.