(x-1)(x+2) = x^2+ rx + s
What is "r" and "s"??
Help!! f.4 Mat
2009-06-09 4:06 am
回答 (1)
2009-06-09 4:08 am
✔ 最佳答案
We just expand the L.H.S.L.H.S. = (x - 1)(x + 2)
= x2 - x + 2x - 2
= x2 + x - 2
Therefore, by comparing coefficients,
r = 1, s = -2
參考: Physics king
收錄日期: 2021-04-19 14:28:56
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