How do I find 8^(2/3)?

8^(2/3) = 2^2 = 4

8^(2/3)
= ³√(8^2)
= ³√[(2^3)^2]
= ³√[(2^2)^3]
= 2^2
= 4

8^(2/3)

This means it is to the 2/3rds power.

This means it is squared, but also, the cubed root is being taken.

It does not matter what order you do it in, you just need to make sure you do both of them. Just remember when you put something to a fractional power, it is going to be put to a power and then taken to a root.

For example, the square root of 4 is equal to 4^(1/2)
sqrt(4) = 4^(1/2)
2 = 2

So, taking this to our current problem, we can expand a little bit.

8^(2/3)
First, I would take the 3rd root of it, which you can find by finding all the multiples of the number and seeing if you can pull a number out

8^(2/3) = (4*2)^(2/3) = (2*2*2)^(2/3)
Since there is a cube in there, you can pull it out.
8^(2/3) = 2^(2)
Now, you have the power still left over, so you square it.
2^(2) = 4

Four is your final answer.

Third root of 8 is two. Two squared is 4. Therefore, the answer is 4.

You can think of this two different ways:
(1) Take the cube root of 8, then square that answer
(8^(1/3)^2 = (2)^2 = 4
(2) Square 8, then take the cube root of that answer
(8^(2))^(1/3) = (64)^(1/3) = 4

Either way, you get the right answer