need help with an algebra problem!!!! please :)?

👨🏻‍🏫 學術台 數學
2009-06-07 3:27 pm
the problem is:

(2√7 +4)^2


(7 is the only number under the radical)
pleasee try to tell me how you got the answer (:
更新1:

if u cant show ur work, u dont have to.

回答 (5)

2009-06-07 3:32 pm
✔ 最佳答案
(2√7 + 4)^2

= (2√7)^2 + 8√7 + 8√7 + 16

= 28 + 16√7 + 16

= 44 + 16√7
👍 3 👎 0
2009-06-07 10:51 pm
44 +16sqrt7
👍 1 👎 0
2009-06-07 10:41 pm
(2√7 +4)^2
=(2√7+4)(2√7+4)
=4√49+8√7+8√7+16
=4*7+16√7+16
=28+16√7+16
=44+16√7 answer//
參考: http://www.mathway.com/answer.aspx?p=calg?p=(2sqrt(7)SMB15+4)SMB072?p=2?p=?p=?p=?p=?p=?p=?p=0?p=?p=
👍 1 👎 0
2009-06-07 10:35 pm
wat it is saying is:
(2times the square root of 7+4)(2times the square root of 7+4)
*sorry i dont know how to make a radical sign
then u would use the FOIL method
i would continue, but it would get confusing b/c i cant make a radical sign
👍 1 👎 0
2009-06-08 12:18 pm
(2√7 + 4)^2
= (2√7 + 4)(2√7 + 4)
= (2 * 2)√(7 * 7) + (4 * 2)√7 + (2 * 4)√7 + 4*4
= 4(7) + 8√7 + 8√7 + 16
= 28 + 16 + 16√7
= 44 + 16√7
= 4(11 + 4√7)
👍 0 👎 0


收錄日期: 2021-05-01 12:27:12
原文連結 [永久失效]:
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