How do I factorise the equation 12y(squared) - 8y?

4y(3y - 2)
First find a number which goes in 12 and 8.
4 is the number. so you multiply everything by 4y.
4y(something, something)
Now you have to find numbers which multiply by 4 and give you answer 12y and 8y
so 12/4=3
8/4=2
so therefore your answer must be:
4y(3y - 2)
note:we get the minus sigh from the start question which is 12y^2 - 8y

hope i have helped

Factorise 12y² - 8y

Highest common factor is 4y
= 4y×3y – 4y×2

Take out the highest common factor
=4y×(3y – 2)

= 4y(3y – 2)

I hope this helps

12y²-8y
take 4y common
=4y (3y-2)
☺

4y(3y - 2)

4 y ( 3 y - 2 )

12y^2 - 8y
= 4(3y^2) - 4(2y)
= 4y(3y) - 4y(2)
= 4y(3y - 2)

12y^2 -8y
=4y(3y-2)

y( 12y - 8)
y = 0 or y = 8/12

Both terms may be divided by 4y:

4y(y - 2)

And, I think that's it!