Expanding the brackets?

2009-06-07 8:14 am
Can someone pleaseee show me how to expand
3(x+6)(x-2)
更新1:

the answer is 3(x+6)(x-2) how do you get that?

回答 (9)

2009-06-07 8:20 am
✔ 最佳答案
3x^2 +12x - 36
2009-06-07 3:44 pm
3(x + 6)(x - 2)
= 3(x*x + 6*x - x*2 - 6*2)
= 3(x^2 + 6x - 2x - 12)
= 3(x^2 + 4x - 12)
= 3*x^2 + 3*4x - 3*12
= 3x^2 + 12x - 36
2009-06-07 3:23 pm
3(x+6)(x-2)
=3(x^2+4x-12)
=3x^2+12x-36 answer//
2009-06-07 3:23 pm
Answer:
3x squared +12x -36
2009-06-07 3:23 pm
3(x+6)(x-2)

multiply (x+6) & (x-2) first.
that'l become, x squared+ 4x-12

then multiply the answer by three, 3x squared + 12x - 36
參考: I'm a Kumon Math Student Currently studying 3rd Year HS Material
2009-06-07 3:22 pm
distribute 3 by multiplying it to the parenthesis (x+6) so it will be (3x+18)

then, distribute 3x to (x-2) and 18 to (x-2) again..

so the expansion is (3x^2 - 6x + 18x - 36)

after, add the similar terms -6x and 18x are similar terms

so the final answer is (3x^2 + 12x - 36)
2009-06-07 3:21 pm
3(x+6)(x-2) = 3(x^2 - 2x +6x -12 )
= 3(x^2 +4x - 12)
= 3x^2 + 12x - 36
2009-06-07 3:20 pm
it doesn't matter if you multiply the 3 in first or if you multiply the binomials first....either way, you get the same answer.

3(x+6)(x-2)
= 3(x^2 + 6x - 2x - 12)
= 3(x^2 + 4x -12)
= 3x^2 + 12x - 36

(3x+18)(x-2)
= 3x^2 - 6x + 18x - 36
= 3x^2 + 12x - 36

and no offence, but Wavey is wrong.
2009-06-07 3:19 pm
Just multiply everything by 3. it will become.... (3x+18)(3x-6)


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