About Neutralisation (20pts)

When you dissolve Na2CO3 in water , it has pH12 to 13, depending on the concentration. It is a strong base! When compare with the true salt such as NaCl, Na2CO3 is not a true salt. When strong acid reacts with a strong base, it is neutralization. The salt is neutral in water, however a strong base reacts with a weak acid such H2CO3, to form a compound which can further react with a strong acid to form the salt.
2NaOH + H2CO3------>Na2CO3 + H2O (partially neutralized)
Na2CO3 + 2HCl--------->2NaCl + CO2 + H2O (fully neutralized)
Hope you can understand nuetralization which is an exothermic reaction.

In fact, it is neutralization
because Na2CO3 + HCl -> nahco3 + nacl (turn it first)
nahco3 + hcl -> h2o + co2 + nacl (the second step)
Notice! hcl is poton donnor, na2co3 is acceptor.
by the bronsted - lowry theory , it is acid-base reaction (neutralization)

Look!the reaction, the product of whole reaction, there is a gas product formed(co2) , entropy is increased.by the second law of entropy,
-Change of G = Change of H - Temptreature x change of entropy
under standard condition, change of H must -value,so that it must be exothermic reaction.So that reactants absorb energy to break bond , release energy to form bond. As energy of forming bond is higher than breaking , it is exothermic.
By all mean, you can regard the stable of their sturcture. Products are more stable than reactants,so that reactants are release energy to keep more stable.

但係Neutraliztion呢個process應該隨左發熱外應該仲要有一個salt & water produce個喎。應該既係neutraliztion 又係exothermic reaction

it is not regarded as neutralisation because the definition of it is the reaction having water and salt as the only product
in the reaction of Na2CO3 and HCl
Na2CO3(aq) + HCl(l) -----> NaCl(aq) + CO2(g) + H20(l)
it doesn't obey the difinition of neutralisation
so the reaction is not regarded as it
yes.....it is an exothermic reaction , you are right