can you do simultaneous equations? if so help!?

x/2 + y=0 ......... (1)
x+3y=10 ............(2)

frm eq 1

(take 2 as LCM )

x/2 + y/1 = 0

x+ 2y=0 ( cross mutliply..... which makes the denominator 2 to be mutliplied with 0)

this is eq----3

from eq 2 and 3

x+ 3y = 10

x+ 2y = 0

(change the signs)

therefore... y= 10
substiute y=10 in any eq... for example.. EQ 2

x+2y=0
x+ 2(10)=0
x + 20 = 0
x= -20


therefore the ans is...
x = -20 , y=10

Multiply the top equation by 2. The equations are now:
x+2y=0
x+3y=10

Subtract the bottom equation from the top equation:
-y= -10

Multiply both sides by -1:
y=10

Now plug this y value into either equation and solve for x. I'll use the second equation, so:
x+3(10)=10
x+30=10
x= -20

So x= -20, y=10.

easy =)
x = 10
y = -20

x/2 + y = 0
x + 3y = 10

x/2 + y = 0
2(x/2 + y) = 2(0)
x + 2y = 0

....x + 2y = ..0
‒) x + 3y = 10
------------------------------
..........-y = -10

-y = -10
y = -10/-1
y = 10

x/2 + y = 0
x/2 + 10 = 0
x/2 = -10
x = 2(-10)
x = -20

∴ x = -20, y = 10

x + 2y = 0
x + 3y = 10

y = 10
x = - 20

x/2 + y=0 ......... (1)
x+3y=10 ............(2)

(1) x 3:
3x/2 + 3y = 0........ (3)

(3) - (1):
(3x/2 + 3y) - (x + 3y) = 0 - 10

If you solve the above equation, you'll 'eliminate' the y and get a value for x.
Then you substitute the x back into any of the equations and find y.