1.
四個數據的平均數, 中位數及眾數分別是6, 5.5及4。試構寫出這組數據。
2.
七個數據的平均數和中位數都是7, 眾數是2和9。如果其中兩個數據是2和5, 試構寫出這組數據。
3.
試找出五個正整數, 使它們的眾數是4, 中位數是5, 平均數是6, 而最大與最小兩數之差不超過6。(提示 : 有兩組可能答案)
*盡量答得簡短D, 不過要解釋下...
有關平均數, 中位數及眾數的問題(構寫數據)
2009-06-02 7:33 am
回答 (2)
2009-06-02 7:56 am
1) 4, 4, 7, 9
2) 2, 2, 5, 9, 9, 10, 11
3) 4, 4, 5, 7, 10 OR 4, 4, 5, 8, 9
2) 2, 2, 5, 9, 9, 10, 11
3) 4, 4, 5, 7, 10 OR 4, 4, 5, 8, 9
2009-06-02 7:55 am
Q1.Ans is 4,4,7 and 9
Because mean;(4+4+7+9)=6
Median=:(4+7)/2=5.5
Mode:=4
Q2.Ans=2,2,5,7,9,9,15
Because mean(2+2+5+7+9+9+15)/7=7
Median=7
Mode=2 and 9
Q3.Ans is 4,4,5,8,9 or 4,4,5,7,10
Because Mean:(4+4+5+8+9)/5=6
or (4+4+5+7+10)/5=6
Median=5
Mode=4
Different=9-4=5
or 10-4=6
Hope above information can help you!
Because mean;(4+4+7+9)=6
Median=:(4+7)/2=5.5
Mode:=4
Q2.Ans=2,2,5,7,9,9,15
Because mean(2+2+5+7+9+9+15)/7=7
Median=7
Mode=2 and 9
Q3.Ans is 4,4,5,8,9 or 4,4,5,7,10
Because Mean:(4+4+5+8+9)/5=6
or (4+4+5+7+10)/5=6
Median=5
Mode=4
Different=9-4=5
or 10-4=6
Hope above information can help you!
參考: me
收錄日期: 2021-04-13 16:39:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090601000051KK02014