✔ 最佳答案
1. vector a is ( i - 2 j) and let vector b be ( mi+ nj)
| a | = sq root ( 1 + 4)
= sq root 5
a。b= | a | | b | cos angle
= sq root 5 x 3 sq root 3 x cos 180
=-3 sq root 15
a。b = ( i - 2 j) 。 ( mi+ nj)
= m - 2n
1 st equation ..... m- 2n = - 3 sq root 15
let Q vector a = - vector b
Qi - 2Qj = -mi -nj
Q = - m and - 2 Q = -n
2nd equation .... -2m = n
sloving the 2 equations
m = -3/5 sq root 15 and n = 6/5 sq root 15
therefore the coordinate of b is (-3/5 sq root 15 , 6/5 sq root 15)
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2. a。b = 1 x 1 x cos 60
= 1/2
後面唔係好明條題目問乜....