solution to y = 3x + 5 and y = 2x + 3?
回答 (11)
2009-05-28 1:53 pm
✔ 最佳答案
y=3x+5y=2x+3
2x+3=3x+5
2x-3x=5-3
-x=2
x=-2 answer//
plu in x=-2 to y=3x+5
y=3(-2)+5
y=-6+5
y=-1 answer//
2009-05-28 1:38 pm
Value of x:
3x + 5 = 2x + 3
x = - 2
Value of y (1st equation):
= 3[- 2] + 5
= - 6 + 5
= - 1
Answer: x = - 2, y = - 1
Proof (2nd equation):
- 1 = 2(- 2) + 3
- 1 = - 4 + 3
- 1 = - 1
3x + 5 = 2x + 3
x = - 2
Value of y (1st equation):
= 3[- 2] + 5
= - 6 + 5
= - 1
Answer: x = - 2, y = - 1
Proof (2nd equation):
- 1 = 2(- 2) + 3
- 1 = - 4 + 3
- 1 = - 1
2016-10-26 11:05 pm
Substitution skill you're taking between the variables in a unmarried equation and replace it in the different. Or, y = 3x + 2 in a unmarried equation, so that you'll be able to easily plug the 3x + 2 into the different equation to resolve for x: 2x + y = 5 is going to 2x + (3x + 2) = 5 2x + 3x + 2 = 5x + 2 = 5 verify for x: 5x = 5 - 2 = 3 x = 3/5 then you surely can placed the price you got here upon for x into both equation to locate y: y = 3x + 2 is going to y = 3 (3/5) + 2. y = 9/5 + 2 y = 9/5 + 10/5 y = 19/5 so... x = 3/5 and y = 19/5
2009-05-28 2:17 pm
x= -2 and y= -1
2009-05-28 1:51 pm
Use the substitution method to solve this system of two linear equations. Check out my Math Variety blog post on this method and click on ads/links of interest:
http://mathvariety.blogspot.com/2009/04/solving-system-of-two-linear-equations.html
You can apply the transitive property here. It says if a=b and b=c, then a=c. Plug in 2x+3 in for y in the first equation. You have:
2x+3=3x+5
Subtract 3 from both sides:
2x=3x+2
Subtract 3x from both sides:
-x=2
Multiply both sides by -1:
x= -2
Now plug this x value into wither equation and solve for y. I'll use the first equation.
y=3(-2)+5
y= -6+5
y= -1
So, the solution is -2,-1.
http://mathvariety.blogspot.com/2009/04/solving-system-of-two-linear-equations.html
You can apply the transitive property here. It says if a=b and b=c, then a=c. Plug in 2x+3 in for y in the first equation. You have:
2x+3=3x+5
Subtract 3 from both sides:
2x=3x+2
Subtract 3x from both sides:
-x=2
Multiply both sides by -1:
x= -2
Now plug this x value into wither equation and solve for y. I'll use the first equation.
y=3(-2)+5
y= -6+5
y= -1
So, the solution is -2,-1.
2009-05-28 1:25 pm
y = -1, x = -2
2009-05-28 1:24 pm
Y = 2x+3 --> eq1
Y = 3x+5 --> eq2
Eq1-eq2
0=-x-2
X=-2.
Put the x value in eq1
Y= 2(-2)+3
Y=-4+3
Y=-1.
X=-2. Y=-1.
Y = 3x+5 --> eq2
Eq1-eq2
0=-x-2
X=-2.
Put the x value in eq1
Y= 2(-2)+3
Y=-4+3
Y=-1.
X=-2. Y=-1.
2009-05-28 1:20 pm
y = 3x + 5 (solve by using elimination)
y = 2x + 3
....y = 3x + 5
‒) y = 2x + 3
------------------------------
....0 = ..x + 2
0 = x + 2
x = -2
y = 3x + 5
y = 3(-2) + 5
y = -6 + 5
y = -1
∴ x = -2, y = -1
y = 2x + 3
....y = 3x + 5
‒) y = 2x + 3
------------------------------
....0 = ..x + 2
0 = x + 2
x = -2
y = 3x + 5
y = 3(-2) + 5
y = -6 + 5
y = -1
∴ x = -2, y = -1
2009-05-28 1:17 pm
3x+5=2x+3
x=-2
y=3(-2)+5
y=-1
x=-2
y=3(-2)+5
y=-1
2009-05-28 1:16 pm
x= -2
y= -1
y= 3x+5 y+2x+3
3x+5 = 2x+3
x=-2
sub back into any equation
to get y = -1
y= -1
y= 3x+5 y+2x+3
3x+5 = 2x+3
x=-2
sub back into any equation
to get y = -1
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