SOLUTION: 8008
On the other hand,
Given 8 numbers 77889911, how many 8-digit numbers can be form?
SOLUTION: First we assume that the 8 digits are distinct so that the number of permutation is 8!.
As there are two ‘7’,two ‘8’, two ‘9’s and two ‘1’s, the answer is 8!/(2!2!2!2!) .
back to the first problem,
i assume that it's asking:
(WLOG)
WWWWWW ( win x 6) LLLLLLLLLLL ( lose x 11)
then the answer should be 17!/(11!6!) = 12376
but i'm wrong... (sigh)
is that i have misunderstood the question??
please help .__.
更新1:
前一? sorry that i don't know what you are talking about! *sigh*
更新2:
do u mean that the result of last round is fixed?