How do i simplify this?

It cannot be simplified further. There is nothing that will cancel.

= (2[b - 5])/([b + 3[b + 5])
= (2b - 10)/(b² + 5b + 3b + 15)
= (2b - 10)/(b² + 8b + 15)

Answer: (2b - 10)/(b² + 8b + 15)

[2(b - 5)]/[(b + 3)(b + 5)]
= (2*b - 2*5)/(b*b + 3*b + b*5 + 3*5)
= (2b - 10)/(b^2 + 3b + 5b + 15)
= (2b - 10)/(b^2 + 8b + 15)

It is currently factored, not simplified.

To simplify you would first take the top half and simplify it by using the distributive property.

2(b-5) = 2b - 10

Next you would distribute the two binomials left under the division line.

(b+3) (b+5) = b(b+5) + 3(b+5) = b^2 +5b +3b +15
Add the like terms.
b^2 +8b +15

So the final equation would simplify into

2b -10
------------------
b^2 +8b +15

Cannot be simplified as nothing cancels.

l think it is in the simplest form.