Solve, but show your factoring also: 10t^2 +11t +3 = 0?

(10t+5)(10t+6)
(2t+1)(5t+3)

t = -1/2 or t = -3/5

10t^2 + 5t + 6t + 3 = 0
5t(2t +1) + 3(2t +1) = 0
(5t+3)(2t+1)=0

5t+3 =0 2t+1=0
t=-3/5 t=-1/2

start up with the help of factoring out an x x(x^2+5x-6)=0 then component (x^2+5x-6) to (x+6)(x-a million) so x(x+6)(x-a million)=0 set each and every time period =0 x=0 x+6=0 x-a million=0 then verify for x x=0 x=-6 x=a million and those very last 3 numbers are your answer!

10t^2 + 11t + 3 = 0
(5x + 3)(2x + 1)
5x+3=0 or 2x+1=0
x= -3/5 or x= -1/2

( 5 t + 3 ) ( 2 t + 1 ) = 0

t = - 3 / 5 , t = - 1 / 2

10t^2 + 11t + 3 = 0
10t^2 + 6t + 5t + 3 = 0
(10t^2 + 6t) + (5t + 3) = 0
2t(5t + 3) + 1(5t + 3) = 0
(5t + 3)(2t + 1) = 0

5t + 3 = 0
5t = -3
t = -3/5 (-0.6)

2t + 1 = 0
2t = -1
t = -1/2 (-0.5)

∴ t = -3/5 (-0.6), -1/2 (-0.5)

Basically, since all terms are positive, we look for two factors: of 3 (1 and 3) and of 10 (either 1 and 10 or 2 and 5). Recalling FOIL, looking for our O+I=11 in the prospective factors, 5 paired with 1 and 2 paired with 3 gives us the 11. So we have (5t+3)(2t+1) as the factoring.

10² + 11t + 3 = (2t + 1)(5t + 3), so t = -1/2 or -3/5

10t*2+11t+3=0
=> 10t*2+5t+6t+3=0
=>5t(2t +1)+3(2t+1)=0
(2t+1)(5t+3)=0
so t= -1/2; t= -3/5

10x5+ t3 = 24 (23-23) 64.8> 14< = 9-9+0 = 0