Factor completely: 4x^2 - 8x^2y^3?
回答 (6)
2009-05-26 4:02 pm
✔ 最佳答案
4x^2 - 8x^2y^3=4x^2(1-2y^3) answer//
2009-05-26 3:59 pm
Pull 4x^2 from both:
4x^2(1-2y^3)
I dont' see a factorization for the second term, so I think that's as far as you can go.
4x^2(1-2y^3)
I dont' see a factorization for the second term, so I think that's as far as you can go.
2009-05-26 4:00 pm
4x^2 - 8x^2y^3
= 4(x^2 - 2x^2y^3)
= 4x^2(1 - 2y^3)
= 4(x^2 - 2x^2y^3)
= 4x^2(1 - 2y^3)
2009-05-26 4:26 pm
-4x^2(2y^3 - 1 )
2009-05-26 3:59 pm
only common item in both is 4x^2, so that is all you can factor out
so the answer is then
4x^2 * (1 - 2x^2 y^3)
so the answer is then
4x^2 * (1 - 2x^2 y^3)
2009-05-26 3:58 pm
4x^2*(1-4y^3)
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