8=4^3/2 in log form is? (10 pts)?
回答 (8)
2009-05-26 3:29 pm
✔ 最佳答案
8 = 4^(3/2)log(base4) 8 = 3/2
2009-05-26 3:37 pm
Simply take the base number on the right side to be the base of log on the left side:
8 = 4^(3/2)
log₄ 8 = 3/2
Done
8 = 4^(3/2)
log₄ 8 = 3/2
Done
2009-05-26 3:25 pm
8=4^3/2
take logs of both sides:log 8=log4^3/2
using rule of logs:log 8=3/2log4
using another rule of logs:3/2- log (8/4)
so i think it is 3/2 -log 2
take logs of both sides:log 8=log4^3/2
using rule of logs:log 8=3/2log4
using another rule of logs:3/2- log (8/4)
so i think it is 3/2 -log 2
2009-05-26 3:24 pm
The usual (in base 10 or any other base)
log 8 = 3/2 log 4. Since log 4 is about 0.6 and log 8 is about 0.9, this seems pretty easy to verify.
log 8 = 3/2 log 4. Since log 4 is about 0.6 and log 8 is about 0.9, this seems pretty easy to verify.
2009-05-28 8:10 pm
Let log be log to base 4
8 = 4^(3/2)
log 8 = 3/2 log 4
log 8 = 3/2
8 = 4^(3/2)
log 8 = 3/2 log 4
log 8 = 3/2
2009-05-26 3:48 pm
b^y = x → y = log_b(x)
8 = 4^(3/2)
3/2 = log_4(8)
8 = 4^(3/2)
3/2 = log_4(8)
2009-05-26 3:34 pm
log (base 4) 8 = 3/2 is the log form.
4^(3/2) = (64)^(1/2) = 8
4^(3/2) = (64)^(1/2) = 8
2009-05-26 3:30 pm
log form is in the form a=log (baseb) c
which means a is the exponent that makes b = to c
3/2 = log(base4) 8
which means a is the exponent that makes b = to c
3/2 = log(base4) 8
收錄日期: 2021-05-01 12:28:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090526071923AAqcFsN