C programming question?

The problem is *(abc+1) is a character not a string
This will work
printf("%s",abc + 1); // if u want the string from 2nd character to print
or
printf("%c",*(abc+1)); // if u want to print the 2nd character
according to what u want, u use one of the above

*(abc + 1)

That means a pointer to (your pointer plus 1)
pointer(pointer + 1)

Lets say that your pointer -
char* abc = "abcdefgh"

Let is say that your 'a' is in address 1000, but our 'abc' is at location 100.

Which means that abc = 1000 (equals the address it points to)
Or that address locatio 100 holds the value 1000

Then *() is a pointer to what ever is in the brackets.

So we have 'pointer to'( abc + 1)
Which means 'pointer to'( 100 + 1 )

So print("%s",,whatever address 101 points to)
Which is effectively a random address. Sometimes you may get a segment fault, other times it may accidentally point to something printable that just happens to have a string terminator.

how can u add number and character(abcedef+1)
Try again.