phy ~ mechanics

2009-05-27 2:53 am
一個500kg既物件在 5 s 裡由 15ms-1 去到 rest 左,,

咁個令佢減速既力係幾多
更新1:

要成個calculatioin既過程

回答 (2)

2009-05-27 4:44 am
✔ 最佳答案
The solution will be simplier if momentum is used.
Since impulse = change of momentum
i.e. force x time = final momentum - initial momentum
force x 5 = 500 x (0 - 15)
hence, force = - 500 x 15/5 N = -1500 N
The retarding force is equal to 1500 N
2009-05-27 3:56 pm
要使物件at rest,即它的末速度為零,v = 0

初速度,u = 15 ms-1

時間,t = 5 s

假設物件的減速度不變

用v = u + at

0 = 15 + a(5)

加速度,a = -3 ms-2

換句話說,即減速度為3 ms-2

再根據牛頓第二定律

F = ma

F = (500)(3)

所需的減速力,F = 1500 N


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