中二的數學題目！10分！

Let h m be the rise of water

Volume of water increased = h (7^2 * pi) = 154h m^2

Volume of immersed part of the metal pillar = (3)(4)(h+12)/2 = 6h + 72 m^2

Consider
Volume of water increased = Volumn of immersed part of the metal pillar
Then, we have
154h = 6h + 72
h = 18/37 m//

ps 這不是完整地放入水桶(姑且這樣叫它)的題目...?
容後補上圖

2009-05-25 19:04:20 補充：
補充:超凡學生，你...取錯位!?
72/154=0.46753.....=0.468(cor. to 3 sig fig)

2009-05-25 19:11:49 補充：
http://img29.imageshack.us/img29/4434/7009052501183.jpg

我明白!

π(72)(h)=1/2x4x3x12

154h=72

h=0.468


∴=0.468m

49h兀=72+6h
154h=72+6h
148h=72
h=18/37

Let h m be the rise of water level.
兀(7^2)h=4x3÷2x(12+h)
49h兀=72+6h
154h=72+6h
148h=72
h=18/37

Let hm be the rise the water level.
π(72)(h)=1/2x4x3x12
154h=72
h=0.467
∴the rise of water=0.467m

2009-05-26 00:57:45 補充：
Sorry,更正

h=0.468
∴the rise of water=0.468m