How can I do this algebraic fraction?

p+1/5 +p/5
=(6p+1)/5

:))

first element and additionally you get { [(t - 4)(t + 2)]/4t ^2} circumstances { [(t - 3)(t - 2)]/[(t - 4)(t + 3)]} cancel out the (t - 4) t^3 - 3t^2 - 4t + 12 over 4t^3 + 12t^2 then simplify as for the different project you cant element out a 2 because of fact 3 isn't divisible via 2 yet you are able to element out an a and get: a^2 (2a - 3)

(p + 2)/10 + p/5
= (p + 2)/10 + 2p/10
= (p + 2 + 2p)/10
= (3p + 2)/10

p + 2/10 + p/5 = (10p+2+2p)/10 = (12p+2)/10 = (6p+1)/10

if it's (p+2)/10 +p/5
(p+2)/10 + 2p/10
(3p+2)/10

if its (p) + (2/10)+(p/5)
(10p/10)+(2/10)+(2p/10)
(12p+2)/10
(6p+1)/5

=6p/5 + 1/5=1/5 (6p+1)

Get a common denominator, so it becomes one fraction

p + 2/10 + p/5 = 10p/10 + 2/10 + 2p/10

= (10p + 2 + 2p)/10

= (14p + 2)/10

= (7p + 1)/5

The LCD is 10 so:
(10p + 2 + 2p) / 10
(12p + 2) / 10
= (6p + 1) / 5