I know the solution is 0,-2
What are the x-intercepts?
What are the x-intercepts of 7x+x(x-5)=0 ?
2009-05-23 6:20 pm
回答 (7)
2009-05-23 6:25 pm
✔ 最佳答案
7x+x(x-5)= 7x + x^2 - 5x = x^2 + 2x = 0 >>> x=0, x=-2
2009-05-24 4:03 pm
7x + x(x - 5) = 0
x[7 + (x - 5)] = 0
x[7 + x - 5] = 0
x[x - 2] = 0
x = 0
x - 2 = 0
x = 2
â´ x = 0, 2
x[7 + (x - 5)] = 0
x[7 + x - 5] = 0
x[x - 2] = 0
x = 0
x - 2 = 0
x = 2
â´ x = 0, 2
2009-05-24 1:30 am
You just answered your own question. The answer is 0 and -2.
2009-05-24 1:26 am
x^2-2x=0
x=0,y=0
x=2,y=0
x=0,y=0
x=2,y=0
2009-05-24 1:24 am
The function crosses the x axis when y = 0
7x+x^2-5x=0
x^2+2x=0
x(x+2)=0
x=0,-2
{0,0} {-2,0}
7x+x^2-5x=0
x^2+2x=0
x(x+2)=0
x=0,-2
{0,0} {-2,0}
2009-05-24 1:24 am
Multiply out
7x + x^2 -5x = 0
x^2 + 2x =0
x = 0 or x = -2
7x + x^2 -5x = 0
x^2 + 2x =0
x = 0 or x = -2
2009-05-24 1:23 am
x intercepts would be
1,-4
1,-4
收錄日期: 2021-05-01 12:27:00
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