Solve the equation: x^2 +4 = 0?

There are no real solutions. This is true.

x² + 4 = 0
x² = −4
x = ±√(−4)

You cant take the square root of a negative number and get real answers.

There is something called "imaginary numbers", though
x = ±√(−4)
x = ±2√(−1)
x = ±2i

Two imaginary solutions.

Im pretty sure that for your purposes, saying "no real solutions" is good enough. Remember, the word "real" is important. Saying there are no solutions at all isnt exactly correct.

x² + 4 = 0
x² = - 4
x = +/- 4i

Answer: x = 4i, - 4i—imaginary solutions

x ² = - 4 (cannot take square root of - ve number )

x ² = 4 i ²

x = ± 2 i

x^2 + 4 = 0
x^2 = -4
x = ±√(-4)
x = ±√(2^2 * i^2)
x = ±2i (← these are imaginary solutions, so there are no real solutions.)

yea there are no real solutions , the are 2 imaginary solutions

X^2+4=0
X^2=-4
if you take the square root x=√-4 = √4 * √-1 so x = 2√-1 or -2√-1
x=2i , -2i ... 'i' is called the imaginary number and is equal to √-1

x^2 = -4

There is no real number squared that is negative.

so the answer is 2i

x² + 4 = 0 subtract 4
x² = - 4
x = 2i

You should look up complex numbers because there is no real number solution for this problem.

there are no real solutions but you can find solutions using a constant i, i^2 = -1

x^2 = -4
x= 2i

x^2=-4
x=±√-4
=±√-1*√4
=±2√-1

the square root of -1 is i, the imaginary unit. algebraically, we've found that all solutions of this equation are in terms of i: 2i, -2i. thus, there are no "real" solutions (they are both imaginary.)