Simplify (x + 4) ( x + 1) using the FOIL Method or any other method?
回答 (9)
2009-05-23 4:20 pm
✔ 最佳答案
(x + 4) * (x + 1) =(x * x) + (x * 1) + (4 * x) + (4 * 1) =
x² + (x + 4x) + 4 =
x² + 5x + 4
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2009-05-24 7:17 pm
x ² + x + 4 x + 4
x ² + 5 x + 4
x ² + 5 x + 4
2009-05-23 6:24 pm
(x + 4)(x + 1)
= x*x + 4*x + x*1 + 4*1
= x^2 + 4x + x + 4
= x^2 + 5x + 4
= x*x + 4*x + x*1 + 4*1
= x^2 + 4x + x + 4
= x^2 + 5x + 4
2009-05-23 4:57 pm
F-(front x front) O-(outer x outer) I- (inter x inter) L-(last x last)
(x+4)(x+1)
x^2 + 1x + 4x + 4
x^2 + 5x + 4
(x+4)(x+1)
x^2 + 1x + 4x + 4
x^2 + 5x + 4
2009-05-23 4:35 pm
x^2+4x+x+4
x^2+5x+4
x^2+5x+4
2009-05-23 4:30 pm
x^2 + 5x + 4
2009-05-23 4:21 pm
=x^2+5x+4
2009-05-23 4:21 pm
(x+4)(x+1)
FOIL:
x*x + 1*x + 4*x + 4*1
x^2+5x+4
FOIL:
x*x + 1*x + 4*x + 4*1
x^2+5x+4
2009-05-23 4:20 pm
x^2 + x + 4x + 1
x^2 + 5x + 1
x^2 + 5x + 1
收錄日期: 2021-05-01 12:24:04
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