Can you please help me with this inequality problem and show me your steps.
>_ this is an inequality sign 2y-(4y+3) is greater than or equal to 6y+3(y+4)
2y-(4y+3)>_6y +3(y+4)?
2009-05-22 6:12 pm
回答 (7)
2009-05-22 6:29 pm
✔ 最佳答案
2y - (4y + 3) ≥ 6y + 3(y + 4)2y - 4y - 3 ≥ 6y + 3*y + 3*4
-2y - 3 ≥ 9y + 12
-2y - 9y ≥ 3 + 12
-11y ≥ 15
y ≤ 15/(-11)
y ≤ -15/11
2009-05-23 1:22 am
2y - (4y + 3) >= 6y + 3(y + 4)
2y - 4y - 3 >= 6y + 3y + 12
- 15 >= 11y
- 15/11 >= y
y <= - 15/11
Answer: y <= - 15/11
2y - 4y - 3 >= 6y + 3y + 12
- 15 >= 11y
- 15/11 >= y
y <= - 15/11
Answer: y <= - 15/11
2009-05-23 1:24 am
- 2 y - 3 ⥠9 y + 12
- 15 ⥠11 y
y ⤠- 15 / 11
- 15 ⥠11 y
y ⤠- 15 / 11
2009-05-23 1:19 am
2y-4y-3 >6y+3y+12
-2y-3>9y+12
11y<-15
y<-15/11
-2y-3>9y+12
11y<-15
y<-15/11
2009-05-23 1:19 am
combine like terms to get: -2y+3>_9y+12
subtract 3 from both sides to get: -2y>_9y+9
subtract 9y from both sides tho get: -11y>_9
then divde by -11 on both sides to get y<_-9/11
you have to change the sign around when add or divde by a negative.
subtract 3 from both sides to get: -2y>_9y+9
subtract 9y from both sides tho get: -11y>_9
then divde by -11 on both sides to get y<_-9/11
you have to change the sign around when add or divde by a negative.
2009-05-23 1:16 am
The one on the right is bigger.
2009-05-23 1:16 am
2y-(4y+3) ⥠6y +3(y+4)
2y - 4y - 3 ⥠6y + 3y + 12
-2y - 3 ⥠9y + 12
-2y - 3 + 2y - 12 ⥠9y + 12 + 2y - 12
-15 ⥠11y
-15/11 ⥠y
Final answer. :)
2y - 4y - 3 ⥠6y + 3y + 12
-2y - 3 ⥠9y + 12
-2y - 3 + 2y - 12 ⥠9y + 12 + 2y - 12
-15 ⥠11y
-15/11 ⥠y
Final answer. :)
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