how do you do (x-2)(3x-3)=?

(x-2)(3x-3)
= (x)×(3x) + (x)×(−3) + (−2)×(3x) + (−2)×(−3)
= 3x² − 3x − 6x + 6
= 3x² − 9x + 6.

= (x - 2)(3x - 3)
= (x * 3x) + (x * - 3) + (- 2 * 3x) + (- 2 * - 3)
= 3x² - 3x - 6x + 6
= 3x² - 9x + 6

Answer: 3x² - 9x + 6

f-o-i-l
(x - 2)(3x - 3) =
3x^2 - 3x - 6x + 6 =
3x^2 - 9x + 6.

(x - 2)(3x - 3)
= x*3x - 2*3x - x*3 + 2*3
= 3x^2 - 6x - 3x + 6
= 3x^2 - 9x + 6

Must be dumb? More like you want us to do your homework for you. I better get 10 pts for this.

FOIL
1. (x)(3x)=3x^2
2. (x)(-3)=-3x
3. (-2)(3x)=-6x
4. (-2)(-3)=6

Now you combine them all together to get 3x^2-3x-6x=6
Combine like terms to get 3x^2-9x+6

Multiply each term in the first formula to each term in the second:
First term: x * 3x and x * -3 = 3x^2 - 3x
2nd term : -2 * 3x and -2 * -3 = -6x + 6
combine the like terms: 3x^2 -9x +6

(x*3x - x*3) - (2*3x - 2*3) = 3x^2 - 3x - 6x - 6
3x^2 - 9x + 6

(x-2)(3x-3)

x*3x = 3x^2
x*-3 = -3x
-2*3x = -6x
-2*-3 = +6

3x^2-3x-6x+6
3x^2-9x+6

If you are asking brackets to be multiplied :-

3 x ² - 3 x - 6 x + 6

3 x ² - 9 x + 6

If you are asking for solution to :-

( x - 2 ) ( 3 x - 3 ) = 0

x = 2 , x = 1

first multiply x by the two terms in second bracket and then multiply -2 with the two terms in second bracket.

x*3x-3*x-2*3x+2*3
3x^2-3x-6x+6
3x^2-9x+6