(3n+2)(n-2)=0 can someone help me solve and check?
2009-05-21 3:59 pm
Can someone help me to solve and check this equation step by step so that i can understand it? I was thinking foil metod but the =0 threw me off
回答 (7)
2009-05-21 4:03 pm
✔ 最佳答案
You solve for n to make the equation 0.First you take the first set of ()'s.
3n + 2 = 0
3n = -2
n = -2/3
Next you take the second set of ()'s.
n - 2 = 0
n = 2
For the equation to be 0 n has to be equal to -2/3 or 2.
參考: Me
2009-05-21 4:05 pm
3n+2=0
n-2=0
n=-2/3 or 2
n-2=0
n=-2/3 or 2
2009-05-21 4:04 pm
n=2
or
n=-2/3
(Ans)
or
n=-2/3
(Ans)
2009-05-21 4:11 pm
3n+ 2 = 0 n-2=0
n = -2/3 n = 2
3n(n-2) +2(n-2) = 0
3n^2 -6n + 2n -2 =0
3n^2 -4n - 2 =0
n = -2/3 n = 2
3n(n-2) +2(n-2) = 0
3n^2 -6n + 2n -2 =0
3n^2 -4n - 2 =0
參考: solve by me
2009-05-21 4:07 pm
eighter 3n+2 or n-2 must be zero,
if 3n+2=0,then n=-2/3
if n-2=0,then n=2
if 3n+2=0,then n=-2/3
if n-2=0,then n=2
2009-05-21 4:06 pm
(3n + 2)(n - 2) = 0
3n + 2 = 0
3n = -2
n = -2/3
n - 2 = 0
n = 2
â´ n = -2/3, 2
3n + 2 = 0
3n = -2
n = -2/3
n - 2 = 0
n = 2
â´ n = -2/3, 2
2009-05-21 4:05 pm
you should make them two separate parts
first one is:
(3n+2) = 0
3n = -2
n = -2 / 3
second one is:
(n-2) = 0
n = 2
Therefore the answers are
n =-2 / 3 and n = 2
first one is:
(3n+2) = 0
3n = -2
n = -2 / 3
second one is:
(n-2) = 0
n = 2
Therefore the answers are
n =-2 / 3 and n = 2
收錄日期: 2021-05-01 12:24:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090521075908AAMVTtY