how do you simplify 4^(3/2) without using negative exponents?

4^(3/2) = ?

the power 3/2 can be split into two simpler powers 1/2 x 3 which is square root followed by cube

(4^1/2)^3 = 2^3 = 8

OR

the power 3/2 can be split into two simpler powers 3 x 1/2 which is cube followed by square root


(4^3)^1/2 = 64^1/2 = 8

both orders of evaluating powers gives the same answer. However calculating the root first keeps the numbers small

I hope this helps

first you convert it to a sqrt by using the denominator as the root no. so sqrt 4^3 is left then simplify. sqrt 64 then simplify = 8

4^(3/2) = (sqrroot(4))^3 = 2^3 = 8

Simplify 3 2

The description is unclear to me. Do you mean the following? [(y)^(-6)]^(-7) = y^(42) or (y - 6)^(-7) = 1 / (y - 6)^7

Its 8.

8

(a^M)^N=a^MN
(4^3/2=4^1/2)^3=2^3=8

4^(3/2)
= (4^3)^(1/2)
= 64^(1/2)
= √64
= 8

same thing as sqrt(4^3)
so sqrt(64) = 8