Find the prime factorization of 2205!!
I need step by step on how to do this. I am really bad at math!!
Math help pleeeeeaaaassseee?
2009-05-20 3:11 pm
回答 (5)
2009-05-20 3:19 pm
✔ 最佳答案
First find numbers that multiply to make 2205. Then keep doing this with each number until you can't find multiples anymore i.e. the numbers are prime:2205: 451, 5(prime)
451: 11(prime) 41(prime).
So the prime factorization is 5,11,41; 5*11*41 = 2205
參考: Maths pupil
2009-05-20 3:15 pm
2205 = 3 x 3 x 5 x 7 x 7
or
2205 = 3^2 x 5 x 7^2
or
2205 = 3^2 x 5 x 7^2
2009-05-20 4:49 pm
Here's a method that I have been using since elementary school. You just need to know the first few prime numbers, then test them for divisibility.
http://www.flickr.com/photos/dwread/3548385365/
http://www.flickr.com/photos/dwread/3548385365/
2009-05-20 3:18 pm
just divide the number by the primes starting at 3 (2 obviously wont divide into 2205 as its an odd number)
2205 = 3 x 735
2205 = 3 x 3 x 245
2205 = 3 x 3 x 5 x 49 [changed to 5 when 3 wouldnt divide in]
2205 = 3 x 3 x 5 x 7 x 7 [changed to 7 when 5 wouldnt divide in]
and that is 2205 expressed as a product of prime factors
2205 = 3 x 735
2205 = 3 x 3 x 245
2205 = 3 x 3 x 5 x 49 [changed to 5 when 3 wouldnt divide in]
2205 = 3 x 3 x 5 x 7 x 7 [changed to 7 when 5 wouldnt divide in]
and that is 2205 expressed as a product of prime factors
2009-05-20 3:18 pm
This should help... www.790gmat.com/GMATGuruFreePrimeFactorizationProblems.doc
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