fill in the blank: p^3+q^3=(p+q) ( )?
回答 (8)
2009-05-19 4:03 pm
✔ 最佳答案
(p^2 - pq + q^2)
2009-05-19 11:07 pm
Use the "sum of cubes" formula. You might also want to take the time to learn the "difference of cubes" and "difference of squares" formulas too. This will save you a lot of time in the future.
The answer by the way is:
p^2 - pq + q^2
The answer by the way is:
p^2 - pq + q^2
2009-05-19 11:07 pm
= (p+q)(p^2 +pq +q^2)
2009-05-19 11:06 pm
a^3 + b^3 â¡ (a + b)(a^2 - ab + b^2)
p^3 + q^3
= (p + q)(p^2 - pq + q^2)
p^3 + q^3
= (p + q)(p^2 - pq + q^2)
2009-05-19 11:05 pm
p^2-pq+q^2
REMEMBER: a^3 + b^3 = (a + b)(a^2 - ab + b^2)
REMEMBER: a^3 + b^3 = (a + b)(a^2 - ab + b^2)
2009-05-19 11:09 pm
p^3+q^3 = (p+q)(p²-pq+q²)
and
p^3-q^3 = (p-q)(p²+pq+q²)
The acronym for a sum or difference of cubes is SOAP
you'll notice the pattern is (p ? q)(p² ? pq ? q²)
So how do your figure out the ?, use SOAP
S - Same sign as what was between the original cubes
O - Opposite sign that was between the original cubes
AP - Last sign is Always Positive.
and
p^3-q^3 = (p-q)(p²+pq+q²)
The acronym for a sum or difference of cubes is SOAP
you'll notice the pattern is (p ? q)(p² ? pq ? q²)
So how do your figure out the ?, use SOAP
S - Same sign as what was between the original cubes
O - Opposite sign that was between the original cubes
AP - Last sign is Always Positive.
2009-05-19 11:16 pm
(p^2-pq+q^2)
========================================
(p+q)(p^2-pq+q^2)=p^3-p^2q+pq^2+p^2q-pq^2+q^3=
=p^3+q^3
I had to double check it,I studied the identities almost
45 years ago.I am almost 60 years old now.
GOOD LUCK.
========================================
(p+q)(p^2-pq+q^2)=p^3-p^2q+pq^2+p^2q-pq^2+q^3=
=p^3+q^3
I had to double check it,I studied the identities almost
45 years ago.I am almost 60 years old now.
GOOD LUCK.
2009-05-19 11:11 pm
p^3+q^3=(p+q)(p^2-pq+q^2) answer//
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