(4x-7)/(x-2)^2
the answer is
1/(x-2)^2 + 1/(x-2)
why is that?
更新1:
sorry the answer is 1/(x-2)^2 + 4/(x-2)
Partial Fractions
2009-05-20 2:27 am
express in partial fraction
(4x-7)/(x-2)^2
the answer is
1/(x-2)^2 + 1/(x-2)
why is that?
(4x-7)/(x-2)^2
the answer is
1/(x-2)^2 + 1/(x-2)
why is that?
回答 (2)
2009-05-20 2:41 am
2009-05-20 4:34 am
(4x-7)/(x-2)^2
=[4(x-2)+1]/(x-2)^2
=4(x-2)/(x-2)^2+1/(x-2)^2
=4/(x-2)+1/(x-2)^2
=[4(x-2)+1]/(x-2)^2
=4(x-2)/(x-2)^2+1/(x-2)^2
=4/(x-2)+1/(x-2)^2
收錄日期: 2021-04-22 00:38:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090519000051KK01160