A particle of mass m is free to rotate at the end A of a light inextensible string AB of length L fixed at its other end B.
The particle is projected horizontal, a point C on the string strikes a fixed smooth peg so that the radial acceleration of the particle is instantaneously doubled. Find the length of AC.
ANS: L/2
AL app math~circular motion2
2009-05-19 3:16 am
回答 (1)
2009-05-20 5:05 am
✔ 最佳答案
This is easy...Suppose the particle is projected horizontally with a speed of v
Then, the radial acceleration of the particle = mv2 / L
Now, the radial acceleration of the particle is doubled, that is 2mv2 / L = mv2 / (L/2)
So, the radius of the circular path becomes L/2, so the length of AC is L/2
參考: Physics king
收錄日期: 2021-04-19 14:19:49
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