I am revising by doing past papers for my exam and all, and this question came up and i have no idea where to start!
could you please explain it so i know how to do it?
(square root sign over 27 + 3) (square root sign over 6 - square root sign over 2)
They dont have the wierd square root tick thing so ive just put it in words,
please help :)
Maths help, im not really sure what it is?
2009-05-17 10:57 am
回答 (3)
2009-05-17 2:51 pm
✔ 最佳答案
You may do it as follows:(√27 + 3)(√6 - √2)
= (3√3 + 3)(√2⋅√3 - √2)
= 3(√3 + 1)⋅√2(√3 - 1)
= 3√2(√3 + 1)(√3 - 1) ... [Difference of 2 squares]
= 3√2(3 - 1)
= 6√2
2009-05-17 11:24 am
lol. I remember this question from an AQA GCSE exam.
(â27 + 3)(â6 - â2)
= (3â3 + 3)(â6 - â2)
= 3â18 - 3â6 + 3â6 - 3â2
= 3(â9 * â2) - 3â2
= 9â2 - 3â2
= 6â2
(â27 + 3)(â6 - â2)
= (3â3 + 3)(â6 - â2)
= 3â18 - 3â6 + 3â6 - 3â2
= 3(â9 * â2) - 3â2
= 9â2 - 3â2
= 6â2
2009-05-17 11:20 am
use the distributive property
(root27+3)(root6-root2)
=root27(root6-root2)+3(root6-root2)
=root162-root54+3root6-3root2
=9root2-3root6+3root6-3root2
=6root2
(root27+3)(root6-root2)
=root27(root6-root2)+3(root6-root2)
=root162-root54+3root6-3root2
=9root2-3root6+3root6-3root2
=6root2
收錄日期: 2021-05-02 16:56:22
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090517025731AAoDs48