How to factories 17x2 + 70x - 552 = 0?

17x^2 + 70x - 552 = 0

Use the quadratic equation:
x = (-b +/- sqrt(b^2 - 4ac)/2a

a = 17
b = 70
c = -552

x = (-70 +/- sqrt(70^2 - 4(17)(-552)))/2(17)

x = (-70 +/- sqrt(4900 + 37536))/34

x = (-70 +/- sqrt(42436))/34

x = (-70 +/- 206)/34

x = -276/34 or 136/34

x = -138/17 or 4

Factors:
x = -138/17
17x = -138
17x + 138 = 0

x = 4
x - 4 = 0

(17x+ 138)(x - 4) = 0


CHECK:
(17x+ 138)(x - 4) = 17x^2 + 70x - 552
17x^2 - 68x + 138x - 552 = 17x^2 + 70x - 552
17x^2 + 70x - 552 = 17x^2 + 70x - 552
CHECK

17x^2 + 70x - 552 = 0
17x^2 + 138x - 68x - 552 = 0
(17x^2 + 138x) - (68x + 552) = 0
x(17x + 138) - 4(17x + 138) = 0
(17x + 138)(x - 4) = 0

17x + 138 = 0
17x = -138
x = -138/17

x - 4 = 0
x = 4

∴ x = -138/17, 4

I'm assuming 17x2 means 17x^2.
I use the quadratic formula. Sorry I'm not good at factoring.
The answer would be 4 or -138/17.

x=[-35+&-(1225+9384)^1/2]/17=
=4&-138/17
17(x-4)(x+138/17)=
=(x-4)(17x+138)

use the quatratic formula

x = ( -b +- sqrt(b^2 - 4ac) ) / 2a

plz add additional information improving ur question's description...
what is factories..when there is no x term there.... may b i m wrong but u must make ur question clear..