what is (3+9i)-(12-5i)?
回答 (6)
2009-05-17 8:50 am
✔ 最佳答案
(3 + 9i) - (12 - 5i)= 3 - 12 + 9i - (-5i)
= -9 + 9i + 5i
= -9 + 14i
2009-05-17 6:10 pm
(3 + 9i) - (12 - 5i)
= 3 + 9i - 12 + 5i
= 3 - 12 + 9i + 5i
= -9 + 14i
= 3 + 9i - 12 + 5i
= 3 - 12 + 9i + 5i
= -9 + 14i
2009-05-17 4:27 pm
3 + 9 i - 12 + 5 i
- 9 + 14 i
- 9 + 14 i
2009-05-17 3:56 pm
You just add the ones with the same coefficient.
(a+bi) + (c+di) = (a+c) + (b+d) i
Thus, the answer to your question is:
-9 + 14i
Hope this helps :)
(a+bi) + (c+di) = (a+c) + (b+d) i
Thus, the answer to your question is:
-9 + 14i
Hope this helps :)
2009-05-17 3:54 pm
3+9i-(12-5i)=3+9i-12+5i
= -9 +14i
modulus is (81 + 196)^1/2
=(277)^1/2
= -9 +14i
modulus is (81 + 196)^1/2
=(277)^1/2
2009-05-17 3:50 pm
-9 + 14i
收錄日期: 2021-05-01 12:29:03
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