You really want to do it by hand? Frankly, it will be quite clumsy but if it is an assignment, it will be desperately a piece of hard work. Yeh it is POSSIBLE to do it WITHOUT a calculator and... there you go.
* * *
To simplify the work, I'll set more variables to get rid of the clumsy numbers.
Let a = 108^.5 and b = 10;
so X will be (a+b)^(1/3)
& Y will be (a-b)^(1/3).
Let S be the expression,
i.e. S = X - Y
Taking cube on both sides, ...[trying to get rid of the nasty cubic roots]
S^3
= (X-Y)^3 .............. [still remember binomial theorem?]
= X^3 - 3(X^2)Y + 3X(Y^2) - Y^3
= X^3 - Y^3 - 3XY(X-Y) ............[note that S = X - Y]
= (a+b) - (a-b) - 3[(a+b)(a-b)]^(1/3) x S
= 2b - 3[(a^2 - b^2)]^(1/3) x S
= 2 x 10 - 3(108-100)^(1/3) x S ......[8^(1/3) = 2]
= 20 - 6S
i.e. S^3 + 6S - 20 = 0
(S - 2)(S^2 + 2S + 10) = 0
For S^2+2S+10=0,
∆ = -36 < 0 i.e. no real solution