我有d maths 唔識 大家可唔可以教吓我
解方程
4(x-0.1)2 = (2x-0.3)2
方法不限
回答 (3)
4(x-0.1)^2 = (2x-0.3)^2
4(x^2 + (0.1)^2 - 2x(0.1)) = (2x)^2 + 0.3^2 - 2(2x)(0.3)
4x^2 + 0.04 - 0.8x = 4x^2 + 0.6 - 1.2x
0.04 - 0.8x = 0.6 - 1.2x
0.4x = 0.56
x = 1.4
2009-05-16 18:29:39 補充:
唔好意思...上面有錯~~
睇呢個↓↓
4(x-0.1)^2 = (2x-0.3)^2
4(x^2 + (0.1)^2 - 2x(0.1)) = (2x)^2 + 0.3^2 - 2(2x)(0.3)
2009-05-16 18:29:56 補充:
4x^2 + 0.04 - 0.8x = 4x^2 + 0.09 - 1.2x
0.04 - 0.8x = 0.09 - 1.2x
0.4x = 0.05
x=0.125
我用一個同001有d唔同既方法做一次。
4(x-0.1)2 = (2x-0.3)2
[2(x-0.1)]2=(2x-0.3)2
2(x-0.1)=2x-0.3 或 2(x-0.1)=-(2x-0.3)
2x-0.2=2x-0.3 或 2x-0.2=-2x+0.3
無解 或4x=0.5
x=0.125//
4[X^2-2(X)(0.1)+(0.1)^2]=(2X)^2-2(2X)(0.3)+(0.3)^2
4X^2-0.8X+0.01=4X^2-1.2X+0.09
-0.8X+1.2X=4X^2-4X^2+0.09-0.01
0.04X=0.08
X=0.08/0.04
X=2
4^2=4既2次方
2009-05-16 16:20:13 補充:
以下先係正確,唔好意思
4(X-0.1)^2=(2X-0.3)^2
4[X^2-2(X)(0.1)+(0.1)^2]=(2X)^2-2(2X)(0.3)+(0.3)^2
4(X^2-0.2X+0.01)=4X^2-1.2X+0.09
4X^2-0.8X+0.04=4X^2-1.2X+0.09
-0.8X+1.2X=4X^2-4X^2+0.09-0.04
0.4X=0.05
X=0.05/0.4
X=0.125
4^2=4既2次方
收錄日期: 2021-04-23 20:44:13
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090516000051KK01115
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