Another math problemm?

As 16 = 2x2x2x2 = 2^4,

2^(x+3) = 16^x

2^(x+3) = (2^4)^x

2^(x+3) = 2^(4x)

x+3 = 4x

x = 1

Answer B.

Make the base power to be the same!
2^(x+3)=16^x
2^(x+3)=2^(4x)
X+3=4x
3x=3
X=3.

Dont hate maths! :)

2^(x + 3) = 2^(4x)

x + 3 = 4 x

x = 3

OPTION A

2^(x + 3) = 16^x
2^(x + 3) = (2^4)^x
2^(x + 3) = 2^(4x)
x + 3 = 4x
x - 4x = -3
-3x = -3
x = -3/-3
x = 1
(answer B)

Answer: B

Given 2^(x+3)=16^x
we know that 16^x = 2^(4x) [16=2^4]
hence 2^(x+3)=2^4x

since the base [i.e 2 in this case] is same for LHS and RHS, consider only the power factors to solve the equation

therefore x+3=4x
3=4x-x
3=3x
x= 3/3 = 1

x=1
answers is B

b. 1

16^x is the same as 2^4(x)

so ignore the 2's on both sides of the equation which leaves you with

x+3=4x
solve for x

2^(x+3) = 16^x
→ 2^(x+3) = (2^4)^x
→ 2^(x+3) = (2)^4x
→ (x+3) = 4x
that gives x = 1
hence B.

B.1

2^(3+1) = 16

16^1 = 16

Therefore has to be Answer B. 1

2(x+3)=16x
ie 2x+6=16x
ie 6=16x-2x
ie 6=14x
ie 3=7x
therefore x =7/3.
theregore answer is d