I need to factor that equation how is this done?
Also, would xy - 6 + 2y - 3x be done the same way?
Thanks a lot in advance guys
How do I factor 8ac + 12ad + 10bc + 15bd?
2009-05-14 12:56 pm
回答 (7)
2009-05-14 1:09 pm
✔ 最佳答案
8ac + 12ad + 10bc + 15bd4a(2c+3d) + 5b(2c+3d)
(4a + 5b) (2c + 3d) are the factors
yes...the same can be done in the other equation
u have to group the the terms into two then factorize
xy - 6 + 2y - 3x
xy - 3x + 2y - 6
x(y-3) + 2(y-3)
therefore the whole term is factorize as (x + 2) (y - 3)
2009-05-14 8:00 pm
2c(4a+5b)+3d(4a+5b)
= (4a+5b)(2c+3d)
and yes. the other equation is done in the same way
= (4a+5b)(2c+3d)
and yes. the other equation is done in the same way
2009-05-14 10:10 pm
8ac + 12ad + 10bc + 15bd
= (8ac + 12ad) + (10bc + 15bd)
= 4a(2c + 3d) + 5b(2c + 3d)
= (2c + 3d)(4a + 5b)
= (8ac + 12ad) + (10bc + 15bd)
= 4a(2c + 3d) + 5b(2c + 3d)
= (2c + 3d)(4a + 5b)
2009-05-14 9:24 pm
(4a+5b)(2c+3d)
2009-05-14 8:08 pm
8ac + 12ad + 10bc + 15bd
=4a(2c+3d)+5b(2c+3d)
=(2c+3d)(4a+5b) answer//
xy - 6 + 2y - 3x
=xy-3x+2y-6
=x(y-3)+2(y-3)
=(x+2)(y-3) answer//
=4a(2c+3d)+5b(2c+3d)
=(2c+3d)(4a+5b) answer//
xy - 6 + 2y - 3x
=xy-3x+2y-6
=x(y-3)+2(y-3)
=(x+2)(y-3) answer//
2009-05-14 8:02 pm
(4a + 5b)(2c + 3d)
(x + 2)(y - 3)
(x + 2)(y - 3)
2009-05-14 8:01 pm
you cannot factorize the first equation any further than you have show-en, they are not "like terms" all i can think to do is square root each one.
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