如何找出此多項式?

2009-05-14 4:33 pm
F(x)是一個八次以下的多項式,通過(1, 3)(2, 5)(3, 7)(4, 11)(5, 13)(6, 17)(7, 19)(8, 23)(9, 29)

找出F(x)?
更新1:

Thank you for your answer. It does be really helpful to me, but I still have some question about the Larange interpolation formula. Can it generate all of the polynomials which have power no more than 8? Is the polynomial pass the specific 9 points unique?

更新2:

Could you state the theory about Larange Interpolation Formula more detailed please?

更新3:

thank you very much^^.

回答 (2)

2009-05-14 4:57 pm
✔ 最佳答案
你可以參照知識長Audrey Hepburn早前的解答
http://hk.knowledge.yahoo.com/question/question?qid=7008090802308


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2009-05-15 08:26:12 補充:
It can generate any polynomial you wish which passes through the required coordinates, in any degree.

If 9 points are given, then the degree is 8.

If 5 points, degree is 4.

So, if n points are given, the degree of the polynomial is n - 1

2009-05-15 08:27:28 補充:
This is not a unique polynomial which passes through the 9 points.

But for a polynomial with degree 8, it is unique.

If the degree is higher than 8, then there will be infinitely many polynomials which suit the requirement.
參考: Physics king
2009-05-14 4:45 pm
先用前面7個找出一7次多項式,後而兩個驗算用
F(X)=a(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)+b(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)
+c(x-1)(x-2)(x-3)(x-4)(x-5)+d(x-1)(x-2)(x-3)(x-4)+e(x-1)(x-2)(x-3)+f(x-1)(x-2)+f(x-1)+g
F(1)=g=3
F(2)=f+g=5 f=2
....


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