更新1:
2x + 1 / 5 - 3x 1 - 2x / 3x - 5 2x + 1 / 3x + 5 2x + 1 / 3x - 5 -2x + 1 / 3x + 5 which one
Reduce to lowest terms: 2x2 - 3x - 2 / 10 + x - 3x2?
回答 (4)
2009-05-13 3:16 pm
✔ 最佳答案
2x^2-3x-2---------------
10+x-3x^2
..2x^2-3x-2
=-----------------
..-3x^2+x+10
..2x^2-3x-2
=----------------
..-(3x^2-x-10)
..(2x+1)(x-2)
=-----------------
..-(3x+5)(x-2)
.......2x+1
= - ---------- answer//
.......3x+5
2009-05-13 3:25 pm
(2x^2 - 3x - 2)/(10 + x - 3x^2)
= (2x^2 + x - 4x - 2)/[-(3x^2 - x - 10)]
= [(2x^2 + x) - (4x + 2)]/[-(3x^2 + 5x - 6x - 10)]
= [x(2x + 1) - 2(2x + 1)]/{-[(3x^2 + 5x) - (6x + 10)]}
= [(2x + 1)(x - 2)]/{-[x(3x + 5) - 2(3x + 5)]}
= [(2x + 1)(x - 2)]/{-(3x + 5)(x - 2)}
= -(2x + 1)/(3x + 5)
= (2x^2 + x - 4x - 2)/[-(3x^2 - x - 10)]
= [(2x^2 + x) - (4x + 2)]/[-(3x^2 + 5x - 6x - 10)]
= [x(2x + 1) - 2(2x + 1)]/{-[(3x^2 + 5x) - (6x + 10)]}
= [(2x + 1)(x - 2)]/{-[x(3x + 5) - 2(3x + 5)]}
= [(2x + 1)(x - 2)]/{-(3x + 5)(x - 2)}
= -(2x + 1)/(3x + 5)
2009-05-13 3:14 pm
You need to clarify whether it is the whole of the left divided by the whole of the right, also whether the 'x' between 2 numbers is an unknown or a multiplication sign.
If it is a multiplication, I would give this answer:
2x2 - 3x - 2 / 10 + x - 3x2
= 4 - 3x - 2 / 10 + x - 6
= 2 - 3x / 4 + x
If it is a multiplication, I would give this answer:
2x2 - 3x - 2 / 10 + x - 3x2
= 4 - 3x - 2 / 10 + x - 6
= 2 - 3x / 4 + x
2009-05-13 3:13 pm
2x^2 - 3x - 2 / 10 + x - 3x^2
Find the roots
(2x + 1)(x - 2)/(-3x - 5)(x - 2)
Cancel Like Terms
(2x + 1)/(-3x - 5)
Find the roots
(2x + 1)(x - 2)/(-3x - 5)(x - 2)
Cancel Like Terms
(2x + 1)/(-3x - 5)
收錄日期: 2021-05-01 12:25:58
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